[Cryptech Core] dnssec signer

[Peter Stuge]

Rob Austein wrote:
> > Do I get it right, that for SHA-256 internal state is defined by eight 
> > 32-bit words (h0..h7)?
> 
> Er, I'm guessing you mean the H registers (H0..H7); "h" is part of a
> different series of registers (a..h).
> 
> I *think* you're correct that the state we care about is the H
> registers.

The internal state in the SHA-256 implementation by Tom St Denis is 8
32-bit state words, two 32-bit length words (total bits and intermediate
bytes) and 0..63 bytes of intermediate state (input bytes) where the
latter are compressed away into the former 8 state words each time a
64th input byte becomes available.


//Peter